find the sum of the first 12 terms of an=4n+1
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find the sum of the first 12 terms of an=4n+1
find the sum of the first 12 terms of an=4n+1
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Answer:
s12=324
Step-by-step explanation:
an=4n+1
a1=4(1)+1
a1=4+1
a1=5
an=4n+1
a12=4(12)+1
a12=48+1
a12=49
5,...,49
sn=n/2(a1+an)
s12=12/2(5+49)
s12=6(54)
s12=324