find the value of a such that PQ=QR where P,Q and R are the points whose coordinate are (6,-1),(1,3) and (a,8) respectively.
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find the value of a such that PQ=QR where P,Q and R are the points whose coordinate are (6,-1),(1,3) and (a,8) respectively.
P(6,-1), Q(1,3) and R(x, 8) are the given points.
(6 – 1)² + (–1 – 3 )² = (x – 1)² + (8 – 3)²
(5)² + (–4)² = x² + 1 – 2x + 25
25 + 16 = x² + 1 – 2x + 25
41 = x² – 2x + 26
x² – 2x + 26 – 41 = 0
x² – 2x – 15 = 0
x (x – 5) +3 (x – 5) = 0
(x + 3) (x –5) = 0
x = –3 or x = 5