Find the values of J and D if x-1 and x + 2 are the factors of P(x) = 2x ^ 3 + J * x ^ 2 + Dx + 6
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Find the values of J and D if x-1 and x + 2 are the factors of P(x) = 2x ^ 3
Find the values of J and D if x-1 and x + 2 are the factors of P(x) = 2x ^ 3 + J * x ^ 2 + Dx + 6
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Answer: We couldn't find any more results for ' has 2 zeros 1 and 4. has zeroes , of them same as those of ,viz and and third one say Then product of zeros by Vieta rule is Again by Vieta rule Sum of zeros Writing the value of a in (1) Plugging in and setting it to'.
Step-by-step explanation:
2x3+ax2+bx−4 \tag 1
x2−5x+4 \tag 2
x2−5x+4 has 2 zeros 1 and 4.
2x3+ax2+bx−4 has 3 zeroes , 2 of them same as those of ,viz 1 and 4 and third one say α.
Then product of 3 zeros by Vieta rule is 1*4*\alpha =\dfrac 4 2=2
α=12
Again by Vieta rule
Sum of zeros =1+4+12=−a2 ⟹ a=−11
Writing the value of a in (1)
2x3−11x2+bx−4(3)
Plugging x=1 in (3) and setting it to 0,
2–11+b−4=0 [math] \[/math] to b=13
a=−11;b=13