find two consecutive positive integers such that the square of the first decreased by 17 equals 4 times the second
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find two consecutive positive integers such that the square of the first decreased by 17 equals 4 times the second
find two consecutive positive integers such that the square of the first decreased by 17 equals 4 times the second
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Answer:
This is my answer snnsnsne
Answer:
7 and 8
Step-by-step explanation:
x^2 - 17 = 4(x+1)
x= 3 and 7
but only 7 satisfies the condition. so 7 and 8