find two numbers whose difference is 4 and the difference their squares is 56
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find two numbers whose difference is 4 and the difference their squares is 56
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Answer:
9, 4
Step-by-step explanation:
a-b = 4
a^2-b^2 = 56
We will use substitution. First we simplify the first equation.
a = b+4
We substitute a with b+4 in the second equation.
(b+4)^2 - b^2 = 56
b^2 + 8b + 16 - b^2 = 56
8b + 16 = 56
b + 2 = 7
b = 5
Then we substitute b with 5 in the first equation to find a.
a - 5 = 4
a = 9