Find x so that x-3, 4x + 7, X + 5... form an arithmetic sequence.
A. 5
B. -4
C. 3
D. -2
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Find x so that x-3, 4x + 7, X + 5... form an arithmetic sequence.
A. 5
B. -4
C. 3
D. -2
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Answer:
D. -2
Step-by-step explanation:
A. 5-3=2
(4×5)+7=27 2, 27, 10
5+5=10 \/ \/
+25 -17---not the same
B. -4-3=-7
(4×-4)+7=-9 -7, -9, 1
-4+5=1 \/ \/
+2 +10---not the same
C. 3-3=0
(4×3)+7=19 0, 19, 8
3+5=8 \/ \/
+19 -11---not the same
D. -2-3=-5
(4×-2)+7=-1 -5, -1, 3
-2+5=3 \/ \/
+4 +4---desame
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Verified answer
Answer:
-2
Step-by-step explanation:
4x+7-(x-3)=x+5-(4x+7)
3x+10=-3x-2
6x=-12
x=-2