From point 3.5m away from the foot of the tres, a man found tuhay the height of the tree is 18m. What is the angle of elavation of the top of the tree?
Home
/
From point 3.5m away from the foot of the tres, a man found tuhay the height of the tree is 18m. What is
Answer:
The angle of elevation of the top of a tree of height 18 meters is 30
∘
when measured form a point P in the plane of its base. The distance of the base of the tree from P is
Step-by-step explanation:
Correct option is
D
18
3
m
Distance from tree = x
Length of tree = 18
Let the angle of elevation = 30
∘
Now, tanθ=
distancefromtree
Lengthoftree
tan30=
x
18
3
1
=
x
18
x=18
3
m
#CarryOnLearning
(ノಠ益ಠ)ノ彡┻━┻