f(x)=x2-2x-3
Vertex:
Opening of the point:
Vertex is a___point
Equation of the axis of symmetry:
Domain:
Range:
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f(x)=x2-2x-3
Vertex:
Opening of the point:
Vertex is a___point
Equation of the axis of symmetry:
Domain:
Range:
pa sagot po please
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Verified answer
QUADRATIC FUNCTION
Remember:
Given : f(x) = x²-2x-3
Solution:
We will transform the standard form to vertex form
y=ax²+bx+c to y=a(x-h)²+k
Vertex (h,k)
The vertex is at (1,-4)
It opens upward because the value of a is positive:
equation of the axis of symmetry
Domain
Range
ANSWER
Vertex: (h,k)
Opening of the point: Upward
Vertex is at point (1,-4)
Equation of the axis of symmetry: y = -4
Domain: All real numbers
Range: y ≥ -4
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