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Answer:
The mass of the empty truck can be calculated using the law of conservation of momentum.
Let's assume the delivery truck is moving in the positive direction of the x-axis (to the right), and that the empty truck is moving in the same direction.
The initial momentum (before unloading the delivery truck) is given by
p = mv = (5000 kg) * (8 m/s) = 40000 kg * m/s
Since momentum is conserved, the final momentum (after unloading the delivery truck) must also be 40000 kg * m/s.
The final momentum is given by the empty truck's mass multiplied by its velocity:
p = mv = m * (12 m/s)
Using this equation, we can solve for the mass of the empty truck:
40000 kg * m/s = m * (12 m/s)
Dividing both sides by 12 m/s, we get
m = 40000 kg * m/s / (12 m/s^2) = 3333.3 kg
So the mass of the empty truck is 3333.3 kg.
HOPE IT HELPS
ANSWER:
M= 10000 over 3 kg
SOLUTION:
5000× 8=12M
m = 5000× 8 over 12 = 10000 over 3 kg.