graph the inequality y < 3x + 1
please show the graph and solution :)
thank you in advance
nonsense answer = report
graph can be paper or sa phone lang :) thank you in advance!
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graph the inequality y < 3x + 1
please show the graph and solution :)
thank you in advance
nonsense answer = report
graph can be paper or sa phone lang :) thank you in advance!
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Answer:
find the boundary line then shade the appropriate area
Answer:
First, treat it like an equation:
y=3x−1
This is in the form y=mx+b. m is the slope and b is the y-intercept. In this case, the slope is 3 and the y-intercept is −1. That means it'll start at −1 and for every increase in x, y will increase by 3 and for every decrease in x, y will decrease by 3.
This is what 3x-1 looks like:
graph{y=3x-1 [-10, 10, -5, 5]}
Now we want the part of the graph that is greater than that. That means we shade above it. This would be your final graph:
graph{y>=3x-1 [-10, 10, -5, 5]}
Step-by-step explanation:
Hope it helps
Pls Pa Brainliest
Thank you