How many individual atoms are present in 75.3g.of Ca?
with solution plss
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How many individual atoms are present in 75.3g.of Ca?
with solution plss
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Answer:
13x10^24 Atoms
how many atoms ….. That’s easy enough ….. Use the unit-factor method
75.3g Ca x (6.022x10^23 atoms / 40.1g Ca) = 1.13x10^24 atoms Ca
The conversion factor is a ratio where both the numerator and denominator are equivalent. In this case, both are equivalent to 1 mol of Ca.
Explanation:
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