how many individual atoms are present in 85.7 g of Ca?
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how many individual atoms are present in 85.7 g of Ca?
how many individual atoms are present in 85.7 g of Ca?
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Answer:
Answer. 2.1425 x 6.02 x10^23 = 1.29 x 10^24 (3 s.f.) kasali po ba yung ( 3 s. f.) sa ans.
Explanation:
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