How many real roots does the quadratic equation x² - 4x - I2 = 0 have?
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How many real roots does the quadratic equation x² - 4x - I2 = have?
How many real roots does the quadratic equation x² - 4x - I2 = 0 have?
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Answer:
2
Step-by-step explanation:
x^2 and 4x
i hope it helps
Answer:
b
Step-by-step explanation:
We can use the factoring method for .
To do the factoring method, using the standard form of the quadratic equation , we have to find two numbers that add up to b (in our case, -4) and when multiplied results to c (in our case, -12).
What are the factor pairs of -12?
-12 and 1
-6 and 2
-4 and 3
-3 and 4
-2 and 6
-1 and 12
Which two factors add up to -4?
-12 + 1 = -11
-6 + 2 = -4
-4 + 3 = -1
-3 + 4 = 1
-2 + 6 = 4
-1 + 12 = 11
-6 and 2 add up to -4 and give a product of -12.
So, we put it now as , replacing .
x - 6 = 0
x - 6 + 6 = 0 + 6
x = 6
*****************
x + 2 = 0
x + 2 - 2 = 0 - 2
x = -2
So, x = 6, -2.
These are two roots, so the answer is b.
Hope this helps and #CarryOnLearning! ✨
- sherlockinthemaking -