If 5.0 moles of O2, and 3.0 moles of N2, are placed in a 30.0 L tank at a temperature of 25⁰C, what will the pressure of the resulting mixture of gases be?
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If 5.0 moles of O2, and 3.0 moles of N2, are placed in a 30.0 L tank at a temperature of 25⁰C, what will the pressure of the resulting mixture of gases be?
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Answer:
1250°.c
Explanation:
5.0
+102
=
102
×30.0
=
130.0
+25°.c
=
1250°.c