if f varies jointy as q2 and h, and f=36 when q=2 and h = 3, find f when q= 4 and h = 5. ( a: 48. b: 240. c: 60. d: 15. ) please put your solution.
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if f varies jointy as q2 and h, and f=36 when q=2 and h = 3, find f when q= 4 and h = 5. ( a: 48. b: 240. c: 60. d: 15. ) please put your solution.
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Answer:
The value of f is 240.
Step-by-step explanation:
Mathematical Equation:
[tex]\LARGE\text{$f=kq^2h$}[/tex]
For the constant of variation (k):
Given: [tex]f=36[/tex], [tex]q=2[/tex], [tex]h=3[/tex]
Find: [tex]k=?[/tex]
Formula: [tex]f=kq^2h[/tex]
Solution:
[tex]f=kq^2h\\36=(2)^2(3)k\\36=(4)(3)k\\36=12k\\\frac{36}{12}=\frac{12k}{12}\\\boldsymbol{3=k}[/tex]
For the value of f:
Given: [tex]k=3[/tex], [tex]q=4[/tex], [tex]h=5[/tex]
Find: [tex]f=?[/tex]
Formula: [tex]f=kq^2h[/tex]
Solution:
[tex]f=kq^2h\\f=(3)(4)^2(5)\\f=(3)(16)(5)\\\boxed{\boldsymbol{f=240}}[/tex]
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