if the length of a rectangle is n+4 units, what is its width to obtain an area of n² + 10n+24
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if the length of a rectangle is n+4 units, what is its width to obtain an area of n² + 10n+24
if the length of a rectangle is n+4 units, what is its width to obtain an area of n² + 10n+24
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An area of a rectangle is l x w where l is the length and w is the width.
The length is already given so:
(n+4) x W = n² + 10n+24
we divide (n+3) to both sides so W will be left
W = (n² + 10n+24)/(n+4)
the answer to that will be
W = n+6
Therefore, the width of the given rectangle is n+6 units.
I hope this helps hihi