If the length of the rectangle in terms of x is 8x^2 + 4x + 7 and it's width is 7x +8,what is the perimeter of the rectangle?
pls help po pls
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If the length of the rectangle in terms of x is 8x^2 + 4x + 7 and it's width is 7x +8,what is the perimeter of the rectangle?
pls help po pls
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Answer:
p = 16x² + 22x + 30
Step-by-step explanation:
Let p = perimeter, then;
p = 2(l + w)
p = 2[(8x² + 4x + 7) + (7x + 8)]
p = 2(8x² + 11x + 15)
p = 16x² + 22x + 30
Hope it helps.
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