then what are the length and width of the court?
If the perimeter of a basketball court is 272 feet and the length is 48 feet longer than the width,?
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then what are the length and width of the court?
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Let the width of the court be w feet
therefore,the length is w+48 ft.
According to the problem,
2(w+w+48)=272
2(2w+48)=272
2w+48=272/2=136
2w=136-48=88
w=88/2=44
Therefpre,the width of the court=44 ft
Length of the court=44+48=92 ft
Let x = length, x - 48 = width
Find the length:
2(x + x - 48) = 272
2(2x - 48) = 272
4x - 96 = 272
4x = 368
x = 92
Find the width:
= 92 - 48
= 44
Answer: length is 92 feet, width is 44 feet
Proof (perimeter is 272 feet):
= 2(92 + 44)
= 2 * 136
= 272
perimeter = 272
width = x
length = x + 48
P = 2(length) + 2w, plug in what you know
272 = 2(x + 48) + 2x, distribute the 2
272 = 2x + 96 + 2x, simplify
272 = 4x + 96, subtract 96
176 = 4x, divide by 4
44 = x
width = 44 feet
length = 44 + 48 = 92 feet
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If the perimeter of a basketball court is 272 feet and the length is 48 feet longer than the width,?
then what are the length and width of the court?
let the width be w
length = w + 48
perimeter = w + w + 48 + w + w + 48 = 272
4w = 176
w = 44, length = 92
P=2L+2W
W=L-48
Subtituting the value of W and solving for L: 272=2L + 2(L-48)
2L+2L-96=272
4L=272 +96
L=368/4
L=92 feet
Checking for answers: 272=2(92) + 2(44) =272 okay!
solving for W: W=L-48 = 44 feet
P =( x+y) * 2
and y= x +48
272 = (x+x+48) *2
2x + 48 = 136
2x= 88
x=44 feet
y = x+48 = 44+48 = 92 feet
y = 92 feet
let the width be x
then the length will be x+48
so 2(x+x+48) =272
solve this equation
so x is 44
the length is 92
L = W + 48
272 = 2W + 2W + 96
4W = 176
W = 44 ft
L = 92 ft
2l + 2w = 272
l= 48+ w
2( 48 + w) + 2w = 272
96 + 2w + 2w = 272
4w = 176
w= 44
l = 92