Introductory Activity! What is the remainder when 28 is divided by 2? When it is divided by 4? When it is divided by 7? When it is divided by 14? How are the numbers 2, 4, 7 and 14 related to 282 2, 4, 7, 14, and 28 are factors of 28. Why are those numbers considered as factors of 28?
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Answer:
Find out the smallest number which leaves remainder of 1 when divided by 2, 3, 4, 5, 6 but divided by 7 completely.
What I did is given below step wise.
Step 1- Find out the LCM of 2, 3, 4, 5, 6 which is 60.
Step 2- Add 1 to 60 which is 61.
Step 3- Multiple 61 by 7 repeatedly till it fulfills the condition that remainder should be 1.
I got the answer 146461 which seems to correct.
Step-by-step explanation:
hope it helps po <3
14. 7. 4. 2
Because they are divisible.
Because they can be divisible or can be multiplied by it, it must be even of factors unless its a perfect square.