Jhondy throw an object upward from the top of a 300 ft. tall building. The height of the object, (measured in feet) t seconds after he threw it is h = -4t² + 40t + 300. 1. Where is the object 5 seconds after Jhondy threw it?
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Jhondy throw an object upward from the top of a 300 ft. tall building. The height of the object, (measured in feet) t seconds after he threw it is h = -4t² + 40t + 300. 1. Where is the object 5 seconds after Jhondy threw it?
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Answer:
the object is 400 ft after 5s
Step-by-step explanation: