Joshua is 40 years older than his brother. In ten years he will be twice as old as his brother. What is the present age of each?
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Joshua is 40 years older than his brother. In ten years he will be twice as old as his brother. What is the present age of each?
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Answer:
Joshua is 70 years old.
His brother is 30 years old.
Step-by-step explanation:
Age Word Problem
Age problems are word problems dealing with the ages of people currently, in the past or in the future.
Let us analyze the problem.
Given:
Let x be Joshua's brother age.
Now:
"Joshua is 40 years older than his brother."
Joshua's brother - x
Joshua - x + 40
In 10 years:
"He will be twice as old as his brother."
Joshua's brother - x + 10
Joshua - 2(x + 10) or x + 40 + 10
Equation:
2(x + 10) = x + 40 + 10
Solution:
2(x + 10) = x + 40 + 10
2x + 20 = x + 50
2x - x = 50 - 20
x = 30
Joshua's brother is 30 years old now.
Joshua's age:
x + 40 = 30 + 40 = 70
Joshua is 70 years old.
Final Answer:
Joshua is 70 years old.
His brother is 30 years old.
Checking:
In 10 years:
Brother = x + 10 = 30 + 10 = 40
Joshua = 2(x + 10) = 2(30 + 10) = 2(40) = 80
Twice of 40 is 80. ✔
For examples of age word problems, visit the links:
brainly.ph/question/300535
brainly.ph/question/93745
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