kind of boundary line of 3×-2y>6
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kind of boundary line of 3×-2y>6
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Answer:
First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality.
For: x=0
(3⋅0)−2y=6
0−2y=6
−2y=6
−2y−2=6−2
y=−3 or (0,−3)
For: y=0
3x−(2×0)=6
3x−0=6
3x=6
3x3=63
x=2 or (2,0)
We can now graph the two points on the coordinate plane and draw a line through the points to mark the boundary of the inequality.
The boundary line will be solid because the inequality operator contains an "or equal to" clause.
graph{(x^2+(y+3)^2-0.04)((x-2)^2+y^2-0.04)(3x-2y-6)=0 [-10, 10, -5, 5]}
Now, we can shade the right side of the line.
graph{(3x-2y-6) >= 0 [-10, 10, -5, 5]}
Step-by-step explanation:
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Answer:
for:x=0
(3.0)-2y=6
0-2y=6
-2y=6
-2y-2=6-2
y=3 or (o,-3)
for:y=o
3x-(2x0)=6
3x-0=6
3x=6
3x3=63
x=2or(2,0)