LAS No. 2.31
1. (x2+x+1)(x-1) =
2. (x2-3x+9) (x+3)
3. (x245x+25) (x+5) =
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LAS No. 2.31
1. (x2+x+1)(x-1) =
2. (x2-3x+9) (x+3)
3. (x245x+25) (x+5) =
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1.(x2+x+1)(x−1)
=(x2+x+1)(x+−1)
=(x2)(x)+(x2)(−1)+(x)(x)+(x)(−1)+(1)(x)+(1)(−1)
=x3−x2+x2−x+x−1
=x3−1
2.(x2−3x+9)(x+3)
=(x2+−3x+9)(x+3)
=(x2)(x)+(x2)(3)+(−3x)(x)+(−3x)(3)+(9)(x)+(9)(3)
=x3+3x2−3x2−9x+9x+27
=x3+27
3.(x245x+25)(x+5)
=(x245x+25)(x+5)
=(x245x)(x)+(x245x)(5)+(25)(x)+(25)(5)
=x247+5x246+25x+125
=x247+5x246+25x+125