laws of exponent
(3b)(-5b²c³)(4b³c)
show solution pls
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laws of exponent
(3b)(-5b²c³)(4b³c)
show solution pls
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Answer:
-60b⁶c⁴
Solution :
First we multiply the numerical coefficients first;
(3)(-5)(4) = -60
Second we multiply the variables with exponents , but when we say multiply exponents we mean to add them.
Let's start with b .
(b or b¹) (b²) (b³) → 1 +2+3 = 6 → b⁶
Then c.
(c³)(c or c¹) → 3 + 1 = 4 → c⁴
Then all together , -60b⁶c⁴