3. A spring with constant spring of 15 N/m is extended by 0.5 m. Calculate the elastic potential energy?
Share
3. A spring with constant spring of 15 N/m is extended by 0.5 m. Calculate the elastic potential energy?
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Answer:
I'm assuming that you are asking what is the elastic potential energy stored in the spring at the position stretched by 16.5 cm...
Since you know the spring constant k, 144 N/m and the spring stretch from the equilibrium position x, is 16.5 cm, or 0.165, you find the spring's potential energy from the equation PE =
1
2
k
x
2
, which equals 1.96 Joules, or kg *
m
2
/
s
2
if you want SI units.