Mr. Jackson went to the furniture shop to buy a new dining table for his new home. The dining table has an area of 8x^2-18x+10 square inches. Make an expression that would define the area of 10 inches
Ac method with solution please
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Mr. Jackson went to the furniture shop to buy a new dining table for his new home. The dining table has an area of 8x^2-18x+10 square inches. Make an expression that would define the area of 10 inches
Ac method with solution please
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Answer:
Sure, I can help you with that:
Let's assume the table width is "x" inches, and the table length is "x^2-18x+10" inches
Then, the area of the table is (x^2-18x+10)x = x^3-18x^2+10x
Now, the question states that the table has an area of 8x^2-18x+10 square inches. This means that we can set the expression equal to 8x^2-18x+10 and solve for x, the table width:
x^3-18x^2+10x=8x^2-18x+10
x^3-8x^2-18x^2+8x^2+10x-100=0
Factorizing 8x^2-18x^2+8x^2 and 10x-100, we get:
(x-2)x(x-1)=0
x=2 or x=1
Since the table width must be positive, x=2
Therefore, the width of the table is 2 inches.
edit:
Using the AC method, we can solve this question as follows: First, let x be the length of the table. We have the equation: 8x^2-18x+10=A where A is the area of the table. To determine the width of the table, we can use the formula for the area of a rectangle: A = w * h = (8x-18) * h where w is the width and h is the height. Now we can solve for x, which will give us the width as well. To do this, we need a right-angled triangle with sides proportional to the coefficients o
Step-by-step explanation:
Ps:
example if your confused
3^2 = 3²