1. a 0.15 kg red ball moves on a lane at 1.5 m/s. it collides with and sticks to another blue colored ball of mass 0.10 kg, which was stationary before collision. What is the velocity of the combined balls after collision?
2. a volleyball weighing 1.5kg moves in the court at 1.8/ms. it collides with and sticks to a basketball which mass is 2.2kg. What is the velocity of the combined balls after collision? (auto brainlest kung may sense ang sagot)
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Answer:
These problems are example of conservation of momentum.It states that the sum of initial momenta is equal to the sum of final momentamThe formula is:
M1V1+M2V1=M1V2+M2V2
But in these problems,they produce a type of collision called inelastic collision.Inelastic collision occurs when two bodies collide,and after that,they now move together with a common velocity.The formula for inelastic collision is:
M1V1+M2V1=(M1+M2)V2
1.
Before we solve anything,let us first enumerate what we know:
Before Collision:
M1=0.15 kg
V1=1.5 m/s
M2=0.10 kg
V1=0 m/s(at rest)
Let us now use the inelastic collision formula to find their velocity after they stick together.
M1V1+M2V1=(M1+M2)V2
Substituting and solving for V2:
(0.15)(1.5)+(0.10)(0)=(0.15+0.10)V2
0.225+0=(0.25)V2
0.225=(0.25)V2
V2=0.9 m/s
Therefore,after the collision,they now move together at 0.9 m/s.
2.
Again,before solving,we need to analyze our problem and list what we know:
M1=1.5 kg
V1=1.8 m/s
M2=2.2 kg
V1=0 m/s(Assuming that the basketball is at rest)
Let's use again the inelastic collision formula to solve for their final velocity after they stick together:
M1V1+M2V2=(M1+M2)V2
Substituting and solving for V2,we have:
(1.5)(1.8)+(2.2)(0)=(1.5+2.2)V2
2.7+0=(3.7)V2
2.7=(3.7)V2
V2≈0.73 m/s
Therefore,the volleyball and basketball has a velocity of 0.73 m/s after they collided and stick together.