OBSERVATION #4 Assuming that a gas container has an initial temperature of 200.0% and a volume of 50.0 L and a pressure of 12atm, the change in pressure occurs at 3atm and 5L of its volume and 55°C in its temperature. Calculate the change in volume
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Answer:
Sure, I can help you with that.
Here are the steps involved in calculating the change in volume of the gas container:
1. Convert the temperature from percentage to Kelvin.
2. Use the ideal gas law to calculate the initial volume of the gas.
3. Calculate the final pressure of the gas.
4. Calculate the final volume of the gas.
5. Calculate the change in volume of the gas.
Here are the details for each step:
1. Convert the temperature from percentage to Kelvin:
```
Temperature (°C) = 200.0
Temperature (K) = 200.0 + 273 = 473 K
```
2. Use the ideal gas law to calculate the initial volume of the gas:
```
Initial Pressure (P1) = 12 atm
Initial Volume (V1) = ?
Initial Temperature (T1) = 473 K
Number of moles (n) = 1 mol
Gas Constant (R) = 0.0821 L atm/mol K
(P1)(V1) = (n)(R)(T1)
V1 = (n)(R)(T1) / P1
V1 = (1 mol)(0.0821 L atm/mol K)(473 K) / 12 atm
V1 = 38.8 L
```
3. Calculate the final pressure of the gas:
```
Final Pressure (P2) = 3 atm
```
4. Calculate the final volume of the gas:
```
Final Volume (V2) = ?
Final Pressure (P2) = 3 atm
Final Temperature (T2) = 55°C + 273 = 328 K
Number of moles (n) = 1 mol
Gas Constant (R) = 0.0821 L atm/mol K
(P2)(V2) = (n)(R)(T2)
V2 = (n)(R)(T2) / P2
V2 = (1 mol)(0.0821 L atm/mol K)(328 K) / 3 atm
V2 = 94.4 L
```
5. Calculate the change in volume of the gas:
```
Change in Volume (ΔV) = V2 - V1
ΔV = 94.4 L - 38.8 L
ΔV = 55.6 L
```
Therefore, the change in volume of the gas container is 55.6 L.
Explanation: