pa help po dito ano daw po yung natutuhan ko ayan po yung lesson need ko po may 50 points po ang makakasagot
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pa help po dito ano daw po yung natutuhan ko ayan po yung lesson need ko po may 50 points po ang makakasagot
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Answer:
Speed (velocity) depends on distance and time travel
Further explanation
Linear motion consists of 2: constant velocity motion with constant velocity and uniformly accelerated motion with constant acceleration
At constant velocity motion:
the speed of vo = v = constant
acceleration = a = 0
Δx = vt or x = xo + vt
An equation of constant velocity motion
\rm D=v\times tD=v×t
D =distance , m
v = velocity, m/s
t = time, s
1. speed = v=60 mph, t = 6 hours
\rm D=60\times 6=\boxed{\bold{360~miles}}D=60×6=360 miles
2. distance = d =480 miles, t = 8 hours
\rm v=\dfrac{480}{8}=\boxed{\bold{6~mph}}v=8480=6 mph
3. speed = v = 3 mph, d = 24 miles
\rm t=\dfrac{24}{3}=\boxed{\bold{8~hours}}t=324=8 hours
4. speed = v = 65 mph, t = 4 hours
\rm d=65\times 4=\boxed{\bold{260~miles}}5. speed = v = 6 mph, t = 4 hours
\rm d=6\times 3 =\boxed{\bold{18~miles}}d=6×3=18 miles
6. d = 30 miles, v = 10 mph, initial time = 2:00 pm
\rm t=\dfrac{30}{10}=3~hourst=1030=3 hours
time arrive :
\rm 2:00~pm+3~hours=\boxed{\bold{5:00~pm}}2:00 pm+3 hours=5:00 pm
Learn more
uniformly accelerated motion
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Uniformly accelerated motion: vertical dimension
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Answer:
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