pa help po sa science
Share
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Answer:
1 Sham drops a rock and it hits the ground after 5 seconds. We can calculate the final velocity using equation 1:
v = u + at
Since the rock is dropped, the initial velocity u is zero. The acceleration due to gravity a is -9.8 m/s^2 (negative because it acts downwards). The time t is 5 seconds. Plugging in these values, we get:
v = 0 + (-9.8 m/s^2) * 5s
v = -49 m/s
FINAL ANSWER
Therefore, the final velocity of the rock just before it hits the ground is -49 m/s. The negative sign indicates that the velocity is directed downwards.1
2To determine the final velocity of the rock just before it hits the ground, we can use the equation for free fall motion. The final velocity (Vf) can be calculated using the equation:
Vf² = Vi² + 2gh
where
Vf = final velocity
Vi = initial velocity (which is 0 in this case because the rock is dropped)
g = acceleration due to gravity (approximately 9.8 m/s² near the Earth's surface)
h = height of the building (122.5 m)
Substituting the known values into the equation, we have:
Vf² = 0² + 2 * 9.8 * 122.5
Vf² = 0 + 2 * 9.8 * 122.5
Vf² = 0 + 2401
Vf = √2401
Vf ≈ 49 m/s
Therefore, the final velocity of the rock just before it hits the ground is approximately 49 m/s.