Pakisagot nga kailangan ko lang kase thanks.
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Pakisagot nga kailangan ko lang kase thanks.
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Answer:
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Given: FERM is rhombus and BETH is square.
To find the value of x.
solution:
3. LIFE = x + 20 ,
LIEF = x + 26
Diagonal of rhombus are interset at 90° So. In OFIE
<IFE + LIEF + 90° =180 °
< x + 20 + x + 26 = 90°
2x = 90° - 46° = 44°
x = 22
<IFE=22+20=42, <IEF=x +26=22+26
=48
4. Similarly, In DIMR
<IMR + <IRM + 90° =180°
=) 4x + 20 + 2x + 20 = 180°
=) 6x=60°
x= 20°
<IMR=4x10+20=60°, <IRM=2x10+10
=30°
5. <IFE+<IEF=42°+48°=90°
6. <IMR+<ERM=60+30=90°
7. HM=½HE =) HM=½x40= x+15