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Answer:
a. 6
b. 9
c. 85.5
a 24
b 16
Step-by-step explanation:
a. 3x-9=x+3
3x-x=3+9
(2x=12)/2
x=6
b. UYM=x+3; x=3
UYM= (6)+3=9
c. UYM+YUM=180; consecutive angles of a rhombus are supplementary
9+KUY=180
YUM=180-9
YUM=171
KUY=YUM/2; diagonals bisect opposite angles
KUY=171/2
KUY=85.5
a. If MY+KU=40 ,SU=8, and SU=SK ; diagonals bisect each other..
then KU=SU+SK
KU=SU+SK
KU=8+8
KU=16
MY+KU=40
MY+16=40
MY=40-16
MY=24