please answer po
2. Ethanol, the alcohol contained in alcoholic beverages, is composed of 52.2% C, 13.0% H,
and 34.896 O by mass. its molar mass is 46.0 g mol
(a) what is the empirical formula
ethanol?
(b) What is its molecular formula?
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please answer po
2. Ethanol, the alcohol contained in alcoholic beverages, is composed of 52.2% C, 13.0% H,
and 34.896 O by mass. its molar mass is 46.0 g mol
(a) what is the empirical formula
ethanol?
(b) What is its molecular formula?
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Answer:
Empirical formula = C2H6O
Molecular formula = C2H6O
Explanation:
Step 1: Assume that the mass of ethanol is 100.0 g.
mass C = 52.2 g
mass H = 13.0 g
mass O = 34.8 g
Step 2: Compute for the number of moles of each element.
n C = 52.2 g × (1 mol / 12.011 g) = 4.35 mol
n H = 13.0 g × (1 mol / 1.0078 g) = 12.9 mol
n O = 34.8 g × (1 mol / 15.999 g) = 2.175 mol
Step 3: Divide the number of moles of each element by the least number of moles.
Let CxHyOz be the empirical formula
x = 4.35 mol / 2.175 mol = 2
y = 12.9 mol / 2.175 mol = 5.93 ≈ 6
z = 2.175 mol / 2.175 mol = 1
Step 4: Write the empirical formula.
Empirical formula = C2H6O
Step 5: Compute the empirical mass.
Empirical mass = 2(12.011) + 6(1.0078) + 15.999
Empirical mass = 46.068 g/mol
Step 6: Divide the molar mass by the empirical mass.
Molecular formula = (C2H6O)n
n = molar mass / empirical mass
n = 46.0 g/mol / 46.068 g/mol
n = 0.999 ≈ 1
Molecular formula = (C2H6O)1
Molecular formula = C2H6O
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