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Answer:
9. The figure is about the uses of varried shapes in infrastracture.
10. 4 figures
11. symmetrical?
12. Area of rectange = bh
area of a square = s^2
area of a circle= (πr^2)
area of a triangle= 1/2 (bh)
13. area of the roof
a. area of the rectangle = bh= 20(6) = 120 square feet
b. area of the triangle= 1/2(bh) = 1/2 (5)(5) = 12.5 square units
c. area of the roof = 12.5 + 120 = 132.5 square units.
14. Area of the unshaded part
a. area of the cirxle = pir^2= 3.14(1^2) = 3.14 square ft
b. area of the rectangle = bh= 10 ft (4ft) = 40 square ft
c. are of the unshaded part = 40 - 3.14 = 36.86 square ft
edit: sorry
15. area of the shaded part of the house
first solution
a. area of the unshaded part of the door = 36.86 square ft
b. area of the 2 windows = 2s^2 = 2(2x2)= 8 square ft
c. area of the unshaded part of the house = 36.86 + 8 = 44.86 square ft
second solution
area of all the figures in the house
= area of the roof + area of the biggest rectangle
= 120 square ft + (24x30)
= 120 square ft + 720 square ft
= 840 square ft
third solution
area of the shaded part of the whole house
840 square ft - 44.86 square ft
= 795.14 square ft