Practice Exercise F:
1. A 5.0 L balloon has a pressure of 1.0 L atm at sea level, where the temperature is 28°C. The balloon was let loose and ascended to a height in the where the temperature is 11°C.
(solve)
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Practice Exercise F:
1. A 5.0 L balloon has a pressure of 1.0 L atm at sea level, where the temperature is 28°C. The balloon was let loose and ascended to a height in the where the temperature is 11°C.
(solve)
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SOLUTION:
Step 1: List the given values.
To convert the temperature from degree Celsius to kelvin, add 273 to the temperature expressed in degree Celsius.
[tex]\begin{aligned} & P_1 = \text{1.0 atm} \\ & V_1 = \text{5.0 L} \\ & T_1 = 28^{\circ}\text{C} = \text{301 K} \\ & P_2 = \text{0.65 atm} \\ & T_2 = 11^{\circ}\text{C} = \text{284 K} \end{aligned}[/tex]
Step 2: Calculate the final volume using combined gas law.
[tex]\begin{aligned} \frac{P_1V_1}{T_1} & = \frac{P_2V_2}{T_2} \\ V_2P_2T_1 & = V_1P_1T_2 \\ \frac{V_2P_2T_1}{P_2T_1} & = \frac{V_1P_1T_2}{P_2T_1} \\ V_2 & = \frac{V_1P_1T_2}{P_2T_1} \\ & = \frac{(\text{5.0 L})(\text{1.0 atm})(\text{284 K})}{(\text{0.65 atm})(\text{301 K})} \\ & = \boxed{\text{7.3 L}} \end{aligned}[/tex]
Hence, its volume will be 7.3 L.
[tex]\\[/tex]
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