probability of getting different no. of dots when two dice are rolled?
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probability of getting different no. of dots when two dice are rolled?
probability of getting different no. of dots when two dice are rolled?
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Answer:
The probability is 5/6
Step-by-step explanation:
First roll
1 , 2 , 3 , 4 , 5 , 6
Second roll
1 , 2 , 3 , 4 , 5 , 6
Listing the possible outcomes:
1-1 , 1-2 , 1-3 , 1-4 , 1-5 , 1-6
2-1 , 2-2 , 2-3, 2-4 , 2-5 , 2-6
3-1 , 3-2 , 3-3 , 3-4 , 3-5 , 3-6
4-1 , 4-2 , 4-3 , 4-4 , 4-5 , 4-6
5-1 , 5-2 , 5-3 , 5-4 , 5-5 , 5-6
6-1 , 6-2 , 6-3 , 6-4 , 6-5 , 6-6
There are 36 outcomes , and there are 6 when they are alike in number of dots
Now , 36-6 = 30 is the number of favourable outcomes , Thus
P = Favourable outcomes / Possible outcomes
P = 30 / 36
P = 5/6