PROBLEM 6.1.3
From its position in the periodic table,
determine which atom in each pair is
more electronegative:
a. Br or Cl
b. N or O
c. S or O
d. P or S
e. Si or N
f. Ba or P
g. N or K
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PROBLEM 6.1.3
From its position in the periodic table,
determine which atom in each pair is
more electronegative:
a. Br or Cl
b. N or O
c. S or O
d. P or S
e. Si or N
f. Ba or P
g. N or K
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Answer:
Electronegativity generally increases from left to right across a period and decreases from top to bottom within a group in the periodic table. Using this trend, we can determine the relative electronegativity of the atoms in each pair:
a. Cl is more electronegative than Br because Cl is higher up and further to the right in the periodic table.
b. O is more electronegative than N because O is higher up and further to the right in the periodic table.
c. O is more electronegative than S because O is higher up and further to the right in the periodic table.
d. S is more electronegative than P because S is higher up and further to the right in the periodic table.
e. N is more electronegative than Si because N is higher up and further to the right in the periodic table.
f. P is more electronegative than Ba because P is higher up and further to the right in the periodic table.
g. N is more electronegative than K because N is a nonmetal and K is a metal. Nonmetals are generally more electronegative than metals.