Problem solving
1. What percent (%) of nitrogen (N) in ammonia (NH3)?
2. Find the percentage composition of glucose(C6H12O6)?
3. The molar mass of water (H2O) is 18 grams per mole, how much is the % composition of oxygen?
4. Determine the percentage composition of carbon monoxide (CO).
(matinong sagot naman sana)
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Answer:
1.82.24% percent composition of N and 17.76% percent composition of H
SOLUTION:
14.007+1.008(3)=17.031
14.007)17.031X100=82.24414%
1.008+(3)/17.031X100=17.75586%
2.Molecular mass of glucose (C6H12O6)=6x12+1x12+6x6=72+12+96=180g.
% of carbon (C) in glucose =72/180x100=40
% of hydrogen (H) in glucose=12/180x100=6.66
% of oxygen (O) in glucose=96/180x100=53.33
3.
4.the percent composition of carbon monoxide, the molecule with a chemical formula of CO
42.88%CARBON
57.12%OXYGEN
Explanation:
SA number 3 wait po mejo nalilito ako
Answer:
16÷18=0.88888888889 x 100=88.888888889
O=88.9%