prove my case that if a and b are positive even integers then is de visible by 4?
Pa help po with solution.. Salamat
Share
prove my case that if a and b are positive even integers then is de visible by 4?
Pa help po with solution.. Salamat
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Answer:
Since n is even, we can replace n with 2x where x is some unknown number. Since m is even, we can replace it with 2y. Therefore, nm = 4xy. 4xy must be divisible by 4.
Step-by-step explanation:
Answer:
To prove that if a and b are positive even integers, then a + b is divisible by 4, you can use the following argument:
1. Since a and b are both positive even integers, they can be expressed in the form 2n and 2m, respectively, where n and m are positive integers.
2. Therefore, a + b can be written as (2n) + (2m) = 2(n + m).
3. Since the sum of two even integers is always an even integer, it follows that n + m is an even integer.
4. Therefore, 2(n + m) is divisible by 4, which means that a + b is divisible by 4.
5. We can conclude that if a and b are positive even integers, then a + b is divisible by 4.