Refer to the figure below
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Answer:
a.
3a+4 is the measure of its side
P = 12a+16
b.
A = a²+4a+4
c.
Total Area = 10a²+28a+20
Step-by-step explanation:
a.
Given : A = 9a²+24a+16
Solve for the side of Square ABCD by just factoring the given Area.
A = s²
9a²+24a+16 = s²
[tex] \sqrt{(3a + 4) {}^{2} } = \sqrt{s {}^{2} } [/tex]
3a+4 = s
Solve for Perimeter
P = 4s
P = 4(3a+4)
P = 12a+16
B.
Given: side = a+2
A = s²
A = (a+2)²
A = a²+4a+4
c.
Area of big square + area of small square
9a²+24a+16 + a²+4a+4
9a²+a²+24a+4a+16+4
= 10a²+28a+20