1.How much net force will be required to move a 1,500 kg car with an acceleration of 4m / (s ^ 2)
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1.How much net force will be required to move a 1,500 kg car with an acceleration of 4m / (s ^ 2)
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Answer:
6,000N
Explanation:
Given:
m= 1500kg
a= 4m/s²
F= ?
Formula:
F= m•a
Here is the solution
F=(1500kg•4m/s²)
F=6000N
Thank me later!
Please correct me immidietly if im wrong!
Verified answer
GIVEN:
m = 1, 500 kg
a = 4 m/s²
Fnet = ?
[tex]\\[/tex]
SOLUTION:
[tex]\rm{f = m \: \small• \: a} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ = \rm(1 \: 500 \: kg)(4 \: m/ {s}^{2}) \\ \boxed{\rm f = \rm 6 000N} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: [/tex]