An athlete throws a javelin with a velocity of 28.2 m/s at 42.5 degrees, how far will the javelin go?
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s at 42.5 degrees, how far will the javelin go?
An athlete throws a javelin with a velocity of 28.2 m/s at 42.5 degrees, how far will the javelin go?
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80.76m
Solution: =28.2m/s
=42.5⁰
=(28.2)².2 Sin 42.5⁰. Cos 42.5⁰/9.81
=792.21/9.81
So hence javelin will go 80.76m fast.
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