An airplane from rest accelerates on a runway at 7.5 m/s² for 10.0 s until it finally takes off the ground. What is the distance covered before takeoff? Plsss pasagot po^_^
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An airplane from rest accelerates on a runway at 7.5 m/s² for 10.0 s until it finally takes off the ground. What is the distance covered before takeoff? Plsss pasagot po^_^
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Answer:
37.5
Step-by-step explanation:
Given,
the initial velocity = 0 m /s.
acceleration = 7.5 m / s^2
time = 10s
According to laws of motion.
s = ut + 1/2 at ^2
s = 1/2 at²
s=1/2(7.5 m / s^2)(10)²
s= 37.5m
the distance traveled before takeoff is 37.5m