An Airplane accelerates from rest on a runaway at 7.25m/s² for 15.7s unit it finally takes off the ground. What is the distance covered before takeoff?
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s² for 15.7s unit it finally takes off the ground. What is the distance covered before takeoff?
Answer:
2.17 s
Explanation:
You know the final speed, vf, and the initial speed, vi (which is zero), and you know the acceleration, a. Because vf – vi = at, you know that
t= vf-vi
a
= 15.7m/s - 0m/s
7.25m/s²
t= 2.17 s