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ACCELERATION
FORMULA: Vf = at + Vi
Vf = ( Final Velocity )
a = ( Acceleration)
t = ( Time )
Vi = ( Initial Velocity )
NEED SOLUTION
1. An MRT train accelerates at a rate of 2.75m/s² from rest (0) for 3 seconds. How fast will this train be moving after that time?
2. A cyclist starts from rest (0) and accelerates at 1.5m/s² to a velocity of 15/s. How long did it take the cyclist to attain tha final Velocity
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Answer:
1. Therefore, the MRT train will be moving at a velocity of 8.25 m/s after 3 seconds of acceleration.
2. Therefore, it took the cyclist 10 seconds to attain a final velocity of 15 m/s.
Explanation:
1. Using the formula, Vf = at + Vi, where Vf is the final velocity, a is the acceleration, t is the time taken, and Vi is the initial velocity (which is 0 in this case):
Vf = at + Vi
Vf = (2.75 m/s² x 3 s) + 0
Vf = 8.25 m/s
Therefore, the MRT train will be moving at a velocity of 8.25 m/s after 3 seconds of acceleration.
2. Using the formula, Vf = at + Vi, where Vf is the final velocity, a is the acceleration, t is the time taken, and Vi is the initial velocity (which is 0 in this case):
Vf = at + Vi
15 m/s = (1.5 m/s² x t) + 0
t = 10 seconds
Therefore, it took the cyclist 10 seconds to attain a final velocity of 15 m/s.