a 3kg coconut rolls down with a velocity of 2 m/s. if it stops in 0.5s, how much force is exerted on the sack of rice?
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a 3kg coconut rolls down with a velocity of 2 m/s. if it stops in 0.5s, how much force is exerted on the sack of rice?
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The force acting on an object is given by
where:
F = force
m = mass
a = acceleration
Solving for a
a = -4 m/s²
Solving for F
F = ma
F = (3 kg)(-4 m/s²)
Therefore, the force required to stop the sack of rice is 12 N.
Note: The negative sign of the acceleration and the force indicates that the object is decelerating, meaning, the object is slowing down.