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A 0.050 kg tennis ball approaches a racket at 25 m/s.If it is in contact with the racket's strings for 0.005s,then rebunds at 25 m/s ,what is the average contact force between ball and racket?(Find: Fnet)
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Answer:
Given:
m/Mass=0.050kg
a/Acceleration=25m/s²
F/Force=?
Formula:
F=m•a
=0.050•25m/s²
=1.25kgm/s² or 1.25N
Explanation:
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