A 4.2kg papaya is pushed across a table. If the acceleration of the papaya is 3 m/s^2 to the left, what is the net external force exerted on the papaya?
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A 4.2kg papaya is pushed across a table. If the acceleration of the papaya is 3 m/s^2 to the left, what is the net external force exerted on the papaya?
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The force acting on an object is given by
where:
F = force
m = mass
a = acceleration
Solving for F
F = ma
F = (4.2 kg)(3 m/s²)
Therefore, the net external force exerted on the papaya is 12.6 N.