1. A kite descends to the field of 6 m/s² for 8s until it finally landed off the ground. What is the distance travelled before the kite ascend?
2. a moving plane drop off a package ata a speed of 28m/s
a.) how long will the plane took to attain vertical velocity 9f 196m/s?
b.) what is the range?
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Answer:
1. The distance travelled by the kite before it ascended, assuming no initial velocity at time = 0 and no external forces applied, is given by the following formula:
R = (1/2)gt^2 = (1/2)(6)(8)^2 = 96 meters
2a. The plane takes
t = v/a = 196m/s / 6m/s^2 = 32.67 seconds to attain vertical velocity of 196m/s
2b. The range of the package is given by the following formula:
R = (1/2)(v^2)/g
where v is the initial speed (28m/s in this case) and g is the acceleration due to gravity (6m/s^2 in this case).
R = (1/2)(28^2)/6 = 784 meters
Thus, the range of the package dropped from the plane travelling at 28m/s and reaching a maximum vertical velocity of 196m/s is 784 meters.