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ayan tehhh sana nakatulong
Answer:
The answer in 1 is 2.1
Step-by-step explanation:
x^{2}-6x+9=0
x2−6x+9=0
3
Use the quadratic formula
=
−
±
2
−
4
√
2
x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}
x=2a−b±b2−4ac
Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.
2
−
6
+
9
=
0
x^{2}-6x+9=0
x2−6x+9=0
=
1
a={\color{#c92786}{1}}
a=1
=
−
6
b={\color{#e8710a}{-6}}
b=−6
=
9
c={\color{#129eaf}{9}}
c=9
=
−
(
−
6
)
±
(
−
6
)
2
−
4
⋅
1
⋅
9
√
2
⋅
1